What is the domain of y=(x+2)/(x^2-9) ?

The domain of y=(x+2)/(x^2-9) is x 3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of y=(x+2)/(x^2-9)

domain

y = \frac{x + 2}{x ^{2} - 9}

x < - 3 or - 3 < x < 3 or x > 3

Interval Notation

(- \infty, - 3) \cup (- 3, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = - 3

The function domain

x < - 3 or - 3 < x < 3 or x > 3

b^{y}

\frac{2 ( x + 3 ) ( x - 1 )}{( x - 1 ) ( x + 2 )}

\frac{x - 1}{x ^{2} + 3 x + 2}

g (x) = 2 x - 8 - 3

\frac{x ^{2} - 8 x + 15}{x ^{2} - 5 x + 6}

What is the domain of y=(x+2)/(x^2-9) ?
The domain of y=(x+2)/(x^2-9) is x<-3\lor-3<x<3\lor x>3