What is the domain of h(x)=(sqrt(x^2-4))/2 ?

The domain of h(x)=(sqrt(x^2-4))/2 is x = 2

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domain of h(x)=(sqrt(x^2-4))/2

domain

h (x) = \frac{x ^{2} - 4}{2}

x \leq - 2 or x \geq 2

Interval Notation

(- \infty, - 2] \cup [2, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 2 or x \geq 2

The function domain

x \leq - 2 or x \geq 2

∣ 2 x ∣

f (x) = 7 x - 9

\frac{x - 3}{x - 5}

lo g_{10} (12 - x)

f (x) = \frac{x ^{2} + 5 x - 17}{x ^{2} - 5 x + 6}

What is the domain of h(x)=(sqrt(x^2-4))/2 ?
The domain of h(x)=(sqrt(x^2-4))/2 is x<=-2\lor x>= 2