What is the domain of y=\sqrt[3]{x^2-4} ?

The domain of y=\sqrt[3]{x^2-4} is -infinity <x<infinity

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domain of y=\sqrt[3]{x^2-4}

domain

y = 3 x^{2} - 4

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = - 42 + 2 x

y = 4 x^{2} - 9 x

f (x) = \frac{2 x - 5}{x ^{2} - 4}

f (x) = x^{3} - 2 x

f (x) = 4 (2 x - 4) - 5

What is the domain of y=\sqrt[3]{x^2-4} ?
The domain of y=\sqrt[3]{x^2-4} is -infinity <x<infinity