What is the domain of y=(6-t)/(t^2-t-2) ?

The domain of y=(6-t)/(t^2-t-2) is t 2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of y=(6-t)/(t^2-t-2)

domain

y = \frac{6 - t}{t ^{2} - t - 2}

t < - 1 or - 1 < t < 2 or t > 2

Interval Notation

(- \infty, - 1) \cup (- 1, 2) \cup (2, \infty)

Solution steps

Find undefined (singularity) points:

t = 2, t = - 1

The function domain

t < - 1 or - 1 < t < 2 or t > 2

f (x) = 3 - t

f (x) = \frac{1}{x}

f (x) = \frac{4 x - 1}{5}

E (x) = x^{2} - 4 + 9 - 3 x

f (x) = \frac{3}{x + 1} g (x) = \frac{x}{x - 5}

What is the domain of y=(6-t)/(t^2-t-2) ?
The domain of y=(6-t)/(t^2-t-2) is t<-1\lor-1<t<2\lor t>2