What is the domain of sqrt(x^2+x-6)+4 ?

The domain of sqrt(x^2+x-6)+4 is x = 2

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domain of sqrt(x^2+x-6)+4

domain

x^{2} + x - 6 + 4

x \leq - 3 or x \geq 2

Interval Notation

(- \infty, - 3] \cup [2, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 3 or x \geq 2

The function domain

x \leq - 3 or x \geq 2

\frac{3 x ^{2} - 7 x - 6}{x - 3}

y = \frac{1}{( x + 3 ) \cdot ( x + 2 )}

f (x) = 45 + 6 x

3 x + 2

f (x) = \frac{5 - x}{x ^{2} + 5 x + 6}

What is the domain of sqrt(x^2+x-6)+4 ?
The domain of sqrt(x^2+x-6)+4 is x<=-3\lor x>= 2