What is the domain of y=(2x^2-5x+3)/(4x-10) ?

The domain of y=(2x^2-5x+3)/(4x-10) is x 5/2

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domain of y=(2x^2-5x+3)/(4x-10)

domain

y = \frac{2 x ^{2} - 5 x + 3}{4 x - 10}

x < \frac{5}{2} or x > \frac{5}{2}

Interval Notation

(- \infty, \frac{5}{2}) \cup (\frac{5}{2}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{5}{2}

The function domain

x < \frac{5}{2} or x > \frac{5}{2}

y = 3 2 x + \frac{1}{4}

y = x^{2} - 7 x - 82

\frac{( x + 2 ) ( x + 1 ) ^{2}}{( x + 2 ) ( x - 3 )}

f (x) = \frac{11}{x ^{2} - 100}

x^{2} + 1, x < 0

What is the domain of y=(2x^2-5x+3)/(4x-10) ?
The domain of y=(2x^2-5x+3)/(4x-10) is x< 5/2 \lor x> 5/2