What is the domain of y=sqrt(sin(x))+sqrt(-cos(x)) ?

The domain of y=sqrt(sin(x))+sqrt(-cos(x)) is pi/2+2pin<= x<= pi+2pin

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domain of y=sqrt(sin(x))+sqrt(-cos(x))

domain

y = sin (x) + - cos (x)

\frac{π}{2} + 2 πn \leq x \leq π + 2 πn

Interval Notation

[\frac{π}{2} + 2 πn, π + 2 πn]

Solution steps

Find non-negative values for radicals:

\frac{π}{2} + 2 πn \leq x \leq π + 2 πn

The function domain

\frac{π}{2} + 2 πn \leq x \leq π + 2 πn

f (x) = \frac{1 - x ^{2}}{x - 2}

g (x) = \frac{x + 3}{x ^{2} - 6 x + 9}

3 + ln (x)

y = x^{2} - 4 x + 6

\frac{3 x - 7}{5 x + 6}

What is the domain of y=sqrt(sin(x))+sqrt(-cos(x)) ?
The domain of y=sqrt(sin(x))+sqrt(-cos(x)) is pi/2+2pin<= x<= pi+2pin