What is the domain of f(-3)=(2x^2)/(3x-5) ?

The domain of f(-3)=(2x^2)/(3x-5) is x 5/3

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domain of f(-3)=(2x^2)/(3x-5)

domain

f (- 3) = \frac{2 x ^{2}}{3 x - 5}

x < \frac{5}{3} or x > \frac{5}{3}

Interval Notation

(- \infty, \frac{5}{3}) \cup (\frac{5}{3}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{5}{3}

The function domain

x < \frac{5}{3} or x > \frac{5}{3}

5 x + 15

1.2 x (\frac{700 - 66 x}{55.2})

+ \frac{x}{3} + 2

f (x) = \frac{2 x - 3}{x + 2}

y = 2 + x^{2} - 4 x

What is the domain of f(-3)=(2x^2)/(3x-5) ?
The domain of f(-3)=(2x^2)/(3x-5) is x< 5/3 \lor x> 5/3