What is the domain of f(x)=\sqrt[3]{y/(y-2)} ?

The domain of f(x)=\sqrt[3]{y/(y-2)} is y 2

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domain of f(x)=\sqrt[3]{y/(y-2)}

domain

f (x) = 3 \frac{y}{y - 2}

y < 2 or y > 2

Interval Notation

(- \infty, 2) \cup (2, \infty)

Solution steps

Find undefined (singularity) points:

y = 2

The function domain

y < 2 or y > 2

\frac{x ^{2} - 3}{x ^{2} + 1}

y = lo g_{10} (2 x)

f (x) = ln (\frac{4 - x}{2 + 2 x})

f (x) = 3 x^{2} + 1

2 - \frac{x}{2}

What is the domain of f(x)=\sqrt[3]{y/(y-2)} ?
The domain of f(x)=\sqrt[3]{y/(y-2)} is y<2\lor y>2