What is the perpendicular y=3x,(2,6) ?

The perpendicular y=3x,(2,6) is y=-1/3 x+20/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

perpendicular y=3x,(2,6)

perpendicular

y = 3 x, (2, 6)

y = - \frac{1}{3} x + \frac{20}{3}

Solution steps

Find the line

y = mx + b

perpendicular to

y = 3 x

that passes through

(2, 6)

Find the slope of

y = 3 x : m = 3

Compute the slope of the perpendicular line:

m_{p} = - \frac{1}{3}

Find the line with slope m=

- \frac{1}{3}

and passing through

(2, 6) : y = - \frac{1}{3} x + \frac{20}{3}

y = - \frac{1}{3} x + \frac{20}{3}

x - 3 y = 6

f (x) = \frac{9 + x}{4 - x}

\frac{3 x}{x - 1}

f (x) = \frac{x + 6}{x ^{2} - 3 x - 4}

f (x) = 0.2 (x - 2) (x + 1) (x - 5)

What is the perpendicular y=3x,(2,6) ?
The perpendicular y=3x,(2,6) is y=-1/3 x+20/3