What is the domain of f(x)=(x^4)/(x^2-x-6) ?

The domain of f(x)=(x^4)/(x^2-x-6) is x 3

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domain of f(x)=(x^4)/(x^2-x-6)

domain

f (x) = \frac{x ^{4}}{x ^{2} - x - 6}

x < - 2 or - 2 < x < 3 or x > 3

Interval Notation

(- \infty, - 2) \cup (- 2, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = - 2

The function domain

x < - 2 or - 2 < x < 3 or x > 3

f (x) = \frac{4 x + 5}{x ^{2} - 7}

f (x) = x^{4} + 5

f (x) = x^{2} + x + 4

y = lo g_{10} (4 - 6 x)

f (x) = ln (\frac{( x - 1 )}{( x - 2 )})

What is the domain of f(x)=(x^4)/(x^2-x-6) ?
The domain of f(x)=(x^4)/(x^2-x-6) is x<-2\lor-2<x<3\lor x>3