What is the domain of g(x)= 9/(sqrt(x-3)) ?

The domain of g(x)= 9/(sqrt(x-3)) is x>3

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domain of g(x)= 9/(sqrt(x-3))

domain

g (x) = \frac{9}{x - 3}

x > 3

Interval Notation

(3, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 3

Find undefined (singularity) points:

x = 3

Combine real regions and undefined points for final function domain

x > 3

f (x) = \frac{2 + x + x ^{2}}{5 - 2 x}

\frac{x ^{2} + 1}{x ^{4} + 3 x ^{2} + 1}

f (x) = \frac{x ^{2}}{x ^{2} + x - 2}

x^{4} e^{- x}

f (x) = \frac{( x - 1 ) ( x ^{2} + 4 )}{x ( x + 1 )}

What is the domain of g(x)= 9/(sqrt(x-3)) ?
The domain of g(x)= 9/(sqrt(x-3)) is x>3