What is the domain of sqrt(-x^2-6x+8) ?

The domain of sqrt(-x^2-6x+8) is -sqrt(17)-3<= x<= sqrt(17)-3

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domain of sqrt(-x^2-6x+8)

domain

- x^{2} - 6 x + 8

- 17 - 3 \leq x \leq 17 - 3

Interval Notation

[- 17 - 3, 17 - 3]

Solution steps

Find non-negative values for radicals:

- 17 - 3 \leq x \leq 17 - 3

The function domain

- 17 - 3 \leq x \leq 17 - 3

f (x) = \frac{1}{lo g _{10} ( x ) + 1}

f (x) = - 2 x + 5, - 2 \leq x \leq 2

f (x) = 2 2 x + 4

f (x) = \frac{1}{11 - x}

f (x) = 2500 + 100 x

What is the domain of sqrt(-x^2-6x+8) ?
The domain of sqrt(-x^2-6x+8) is -sqrt(17)-3<= x<= sqrt(17)-3