What is the domain of sqrt(1/(x^2)-1) ?

The domain of sqrt(1/(x^2)-1) is -1<= x<0\lor 0<x<= 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of sqrt(1/(x^2)-1)

domain

\frac{1}{x ^{2}} - 1

- 1 \leq x < 0 or 0 < x \leq 1

Interval Notation

Solution steps

Find non-negative values for radicals:

- 1 \leq x < 0 or 0 < x \leq 1

Find undefined (singularity) points:

x = 0

Combine real regions and undefined points for final function domain

- 1 \leq x < 0 or 0 < x \leq 1

f (x) = \frac{- 3 x}{x - 1}

f (x) = \frac{- x ^{2} + 4}{- x}

f (x) = 81 x

y = \frac{x ^{3}}{8} - \frac{x}{6} + c x^{- 5}

f (x) = \frac{2}{4 x - 1}

What is the domain of sqrt(1/(x^2)-1) ?
The domain of sqrt(1/(x^2)-1) is -1<= x<0\lor 0<x<= 1