What is the domain of f(x)=sqrt(-5x^2+4) ?

The domain of f(x)=sqrt(-5x^2+4) is -2/(sqrt(5))<= x<= 2/(sqrt(5))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=sqrt(-5x^2+4)

domain

f (x) = - 5 x^{2} + 4

- \frac{2}{5} \leq x \leq \frac{2}{5}

Interval Notation

[- \frac{2}{5}, \frac{2}{5}]

Solution steps

Find non-negative values for radicals:

- \frac{2}{5} \leq x \leq \frac{2}{5}

The function domain

- \frac{2}{5} \leq x \leq \frac{2}{5}

f (x) = \frac{2}{4 x - 6}

f (x) = \frac{5 - 2 x}{4 x - 1}

- 2 x^{2} + 14 x - 7

f (x) = - \frac{7}{( 3 + x ) ^{2}}

- ∣ x + 4 ∣ - x

What is the domain of f(x)=sqrt(-5x^2+4) ?
The domain of f(x)=sqrt(-5x^2+4) is -2/(sqrt(5))<= x<= 2/(sqrt(5))