What is the domain of f(x)=(x+7)/(x^2+3x-4) ?

The domain of f(x)=(x+7)/(x^2+3x-4) is x 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=(x+7)/(x^2+3x-4)

domain

f (x) = \frac{x + 7}{x ^{2} + 3 x - 4}

x < - 4 or - 4 < x < 1 or x > 1

Interval Notation

(- \infty, - 4) \cup (- 4, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = - 4

The function domain

x < - 4 or - 4 < x < 1 or x > 1

4 13 - 4 x

f (x) = 3 (\frac{y}{y - 3})

f (x) = 2 + ∣ x ∣

4 x^{3} + 7 x^{2} - 10 x - 8

y = 0.5 (x^{2} - 10 x - 5)

What is the domain of f(x)=(x+7)/(x^2+3x-4) ?
The domain of f(x)=(x+7)/(x^2+3x-4) is x<-4\lor-4<x<1\lor x>1