What is the domain of f(x)=(-6)/(2x+1) ?

The domain of f(x)=(-6)/(2x+1) is x -1/2

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domain of f(x)=(-6)/(2x+1)

domain

f (x) = \frac{- 6}{2 x + 1}

x < - \frac{1}{2} or x > - \frac{1}{2}

Interval Notation

(- \infty, - \frac{1}{2}) \cup (- \frac{1}{2}, \infty)

Solution steps

Find undefined (singularity) points:

x = - \frac{1}{2}

The function domain

x < - \frac{1}{2} or x > - \frac{1}{2}

f (x) = 2 x^{3} - x^{2} + 3

f (x) = \frac{x ^{2} - 8}{x ^{2} + 3 x + 2}

f (x) = \frac{( x + 8 )}{x ^{2} - 16 x + 64}

f (x) = \frac{2 x - 1}{3 x + 5}

f (x) = \frac{6 x + 7}{7 x - 2}

What is the domain of f(x)=(-6)/(2x+1) ?
The domain of f(x)=(-6)/(2x+1) is x<-1/2 \lor x>-1/2