What is the domain of f(x)=arcsin((2x+1)/x-1) ?

The domain of f(x)=arcsin((2x+1)/x-1) is x<=-1/2

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domain of f(x)=arcsin((2x+1)/x-1)

domain

f (x) = arcsin (\frac{2 x + 1}{x} - 1)

x \leq - \frac{1}{2}

Interval Notation

Solution steps

Find known functions domain restrictions:

x \leq - \frac{1}{2}

Find undefined (singularity) points:

x = 0

Combine real regions and undefined points for final function domain

x \leq - \frac{1}{2}

f (x) = \frac{x - 6}{x - 5}

f (x) = - 1 - ln (x)

2 x + 3 + 5

\frac{x ^{2} - 3}{2}

lo g_{10} (4) (5 x - 9)

What is the domain of f(x)=arcsin((2x+1)/x-1) ?
The domain of f(x)=arcsin((2x+1)/x-1) is x<=-1/2