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Popular >

midpoint (-8,-3),(10,9)

Solution

midpoint

(- 8, - 3), (10, 9)

Solution

(1, 3)

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (- 8, - 3), (x_{2}, y_{2}) = (10, 9)

= (\frac{10 - 8}{2}, \frac{9 - 3}{2})

Refine

= (1, 3)

Popular Examples

extreme f(x)=x^2-12x+1 extreme points

f (x) = x^{2} - 12 x + 1

parity sqrt(1+x^2sin^2(x)+x^2cos^2(x))parity

1 + x^{2} sin^{2} (x) + x^{2} cos^{2} (x)

critical f(x)=-x^2+2x-5 critical points

f (x) = - x^{2} + 2 x - 5

domain of f(x)=(x+1)/(sqrt(5x^2-16))domain

f (x) = \frac{x + 1}{5 x ^{2} - 16}

line (2,0),(3,1)line

(2, 0), (3, 1)

Frequently Asked Questions (FAQ)

What is the midpoint (-8,-3),(10,9) ?
The midpoint (-8,-3),(10,9) is (1,3)