What is the domain of f(x)=(x^3+4)/(x^2-25) ?

The domain of f(x)=(x^3+4)/(x^2-25) is x 5

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domain of f(x)=(x^3+4)/(x^2-25)

domain

f (x) = \frac{x ^{3} + 4}{x ^{2} - 25}

x < - 5 or - 5 < x < 5 or x > 5

Interval Notation

(- \infty, - 5) \cup (- 5, 5) \cup (5, \infty)

Solution steps

Find undefined (singularity) points:

x = 5, x = - 5

The function domain

x < - 5 or - 5 < x < 5 or x > 5

\frac{( x ^{3} - x ^{2} - 13 x - 3 )}{( x + 3 )}

f (x) = \frac{- 3 x ^{2}}{8 - x ^{3}}

f (x) = - x (x - 2)^{4} (x + 3)

2 y x - 3 y = 5

f (x) = - x^{2} + 6 x - 9

What is the domain of f(x)=(x^3+4)/(x^2-25) ?
The domain of f(x)=(x^3+4)/(x^2-25) is x<-5\lor-5<x<5\lor x>5