What is the domain of 1+sqrt(|x-1|-1) ?

The domain of 1+sqrt(|x-1|-1) is x = 2

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domain of 1+sqrt(|x-1|-1)

domain

1 + ∣ x - 1 ∣ - 1

x \leq 0 or x \geq 2

Interval Notation

(- \infty, 0] \cup [2, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 0 or x \geq 2

The function domain

x \leq 0 or x \geq 2

f (x) = \frac{( 1 - x )}{x}

f (x) = 6 - x^{2}

\frac{x ^{3}}{x - 4}

3 x^{2} + x - 2

f (x) = lo g_{3} (x^{2} - 3 x - 18)

What is the domain of 1+sqrt(|x-1|-1) ?
The domain of 1+sqrt(|x-1|-1) is x<= 0\lor x>= 2