What is the domain of f(x)=sqrt(x+6-7) ?

The domain of f(x)=sqrt(x+6-7) is x>= 1

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domain of f(x)=sqrt(x+6-7)

domain

f (x) = x + 6 - 7

x \geq 1

Interval Notation

Solution steps

Find non-negative values for radicals:

x \geq 1

The function domain

x \geq 1

∣ x ∣ + ∣ x + 1 ∣ + ∣ 3 - x ∣

f (x) = 9995 \cdot 0.8 2^{0}

f (x) = 5 \cdot x^{2} + 81

ln (- 2 - y^{2})

x^{3} + x

What is the domain of f(x)=sqrt(x+6-7) ?
The domain of f(x)=sqrt(x+6-7) is x>= 1