What is the domain of f(x)=sqrt(x^2-6x+9) ?

The domain of f(x)=sqrt(x^2-6x+9) is -infinity <x<infinity

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domain of f(x)=sqrt(x^2-6x+9)

domain

f (x) = x^{2} - 6 x + 9

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Find non-negative values for radicals:

- \infty < x < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = arccos (x^{2} - 3)

y = \frac{5 x}{2 x - 7}

\frac{x ^{2} - 3}{x ^{3} - 2 x ^{2} - x + 2}

f (x) = (x (x - 5))

22 x - 1694

What is the domain of f(x)=sqrt(x^2-6x+9) ?
The domain of f(x)=sqrt(x^2-6x+9) is -infinity <x<infinity