What is the domain of 2tan(x) ?

The domain of 2tan(x) is pin<= x< pi/2+pin\lor pi/2+pin<x<pi+pin

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domain of 2tan(x)

domain

2 tan (x)

πn \leq x < \frac{π}{2} + πn or \frac{π}{2} + πn < x < π + πn

Interval Notation

Solution steps

Take the denominator(s) of

2 tan (x)

and compare to zero:

x = \frac{π}{2} + πn

Periodicity of

2 tan (x) : π

Combine period:

πn \leq x < π + πn

and undefined points.

The domain is

πn \leq x < \frac{π}{2} + πn or \frac{π}{2} + πn < x < π + πn

f (x) = \frac{( x - 7 )}{( x + 22 )}

f (x) = ln (2 t - 3)

f (x) = \frac{2 x + 7}{4 x ^{2} - 6}

f (x) = \frac{- 3 x}{x ^{2} - 9 x}

f (x) = \frac{1}{9}

What is the domain of 2tan(x) ?
The domain of 2tan(x) is pin<= x< pi/2+pin\lor pi/2+pin<x<pi+pin