What is the domain of f(x)=sqrt(8x+16) ?

The domain of f(x)=sqrt(8x+16) is x>=-2

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domain of f(x)=sqrt(8x+16)

domain

f (x) = 8 x + 16

x \geq - 2

Interval Notation

Solution steps

Find non-negative values for radicals:

x \geq - 2

The function domain

x \geq - 2

2 y + 3

\frac{2 x ^{3}}{x ^{2} - 4}

\frac{4 x + 7}{4 x + 8}

- 4 ∣ x + 2 ∣ + 5

f (x) = x - \frac{9}{x}

What is the domain of f(x)=sqrt(8x+16) ?
The domain of f(x)=sqrt(8x+16) is x>=-2