What is the domain of f(x)=(x^2-9)/(x^2+5x-36) ?

The domain of f(x)=(x^2-9)/(x^2+5x-36) is x 4

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domain of f(x)=(x^2-9)/(x^2+5x-36)

domain

f (x) = \frac{x ^{2} - 9}{x ^{2} + 5 x - 36}

x < - 9 or - 9 < x < 4 or x > 4

Interval Notation

(- \infty, - 9) \cup (- 9, 4) \cup (4, \infty)

Solution steps

Find undefined (singularity) points:

x = 4, x = - 9

The function domain

x < - 9 or - 9 < x < 4 or x > 4

f (x) = \frac{3}{4} x^{2}

f (x) = 2 x^{2} - 4 x - 25

f (x) = - lo g_{2} (x + 2)

f (x) = \frac{x ^{2} + x}{x ^{3} - 9 x}

y = 4^{x} - 3 \cdot 2^{x} + 2

What is the domain of f(x)=(x^2-9)/(x^2+5x-36) ?
The domain of f(x)=(x^2-9)/(x^2+5x-36) is x<-9\lor-9<x<4\lor x>4