What is the domain of f(x)=sqrt(64-x^2)-sqrt(x+2) ?

The domain of f(x)=sqrt(64-x^2)-sqrt(x+2) is -2<= x<= 8

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domain of f(x)=sqrt(64-x^2)-sqrt(x+2)

domain

f (x) = 64 - x^{2} - x + 2

- 2 \leq x \leq 8

Interval Notation

[- 2, 8]

Solution steps

Find non-negative values for radicals:

- 2 \leq x \leq 8

The function domain

- 2 \leq x \leq 8

2 cos (2 x)

π - 2

x + \frac{1}{x} + \frac{1}{x + \frac{1}{x}}

e^{2 x^{2}}

f (x) = \frac{8 + x}{e ^{c o s (x)}}

What is the domain of f(x)=sqrt(64-x^2)-sqrt(x+2) ?
The domain of f(x)=sqrt(64-x^2)-sqrt(x+2) is -2<= x<= 8