What is the domain of arccos(1+x-x^2) ?

The domain of arccos(1+x-x^2) is -1<= x<= 0\lor 1<= x<= 2

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domain of arccos(1+x-x^2)

domain

arccos (1 + x - x^{2})

- 1 \leq x \leq 0 or 1 \leq x \leq 2

Interval Notation

[- 1, 0] \cup [1, 2]

Solution steps

Find known functions domain restrictions:

- 1 \leq x \leq 0 or 1 \leq x \leq 2

The function domain

- 1 \leq x \leq 0 or 1 \leq x \leq 2

\frac{1}{5 ( 5 - x ) ^{2}}

4 - 3 (- 6 n - 2)

4 cot (2 x) + 3

8 - x + 3

f (x) = \frac{2 x ^{2} + 8}{x ^{2} + 9}

What is the domain of arccos(1+x-x^2) ?
The domain of arccos(1+x-x^2) is -1<= x<= 0\lor 1<= x<= 2