What is the domain of f(x)=(ln(x-3))/(sqrt(x^2-x-2)) ?

The domain of f(x)=(ln(x-3))/(sqrt(x^2-x-2)) is x>3

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domain of f(x)=(ln(x-3))/(sqrt(x^2-x-2))

domain

f (x) = \frac{ln ( x - 3 )}{x ^{2} - x - 2}

x > 3

Interval Notation

(3, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 1 or x \geq 2

Find positive values for logs:

x > 3

Find undefined (singularity) points:

x = 2, x = - 1

Combine real regions and undefined points for final function domain

x > 3

f (x) = \frac{7}{x + 4}

x 1 - x^{2}

\frac{1}{4 - 1 - x}

f (x) = \frac{- x ^{3} + 5 x}{x ^{2} + 3}

f (x) = ln (- 1 ∣ x ∣)

What is the domain of f(x)=(ln(x-3))/(sqrt(x^2-x-2)) ?
The domain of f(x)=(ln(x-3))/(sqrt(x^2-x-2)) is x>3