What is the domain of f(x)=arcsin(1-x) ?

The domain of f(x)=arcsin(1-x) is 0<= x<= 2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=arcsin(1-x)

domain

f (x) = arcsin (1 - x)

0 \leq x \leq 2

Interval Notation

[0, 2]

Solution steps

Find known functions domain restrictions:

0 \leq x \leq 2

The function domain

0 \leq x \leq 2

2 x^{2} + x - 3

h (x) = x = 6 x + 5 x - 3

f (\frac{46}{38}) = \frac{2 x + 3}{5 x}

\frac{3}{( \frac{4}{x} ) + 1}

\frac{4 x + 4}{2 x + 8}

What is the domain of f(x)=arcsin(1-x) ?
The domain of f(x)=arcsin(1-x) is 0<= x<= 2