What is the domain of f(x)= 1/(sqrt(x+7)) ?

The domain of f(x)= 1/(sqrt(x+7)) is x>-7

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domain of f(x)= 1/(sqrt(x+7))

domain

f (x) = \frac{1}{x + 7}

x > - 7

Interval Notation

(- 7, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 7

Find undefined (singularity) points:

x = - 7

Combine real regions and undefined points for final function domain

x > - 7

(- 2, 1), (- 4, - 2)

f (x) = \frac{x ^{3} - 27}{x ^{2} + 2 x - 15}

f (x) = ∣ x - 2 ∣

f (x) = x^{2} + y^{2} = 16

f (x) = lo g_{2} (x + 6)

What is the domain of f(x)= 1/(sqrt(x+7)) ?
The domain of f(x)= 1/(sqrt(x+7)) is x>-7