What is the domain of y=(-5x^2-7x)/(sqrt(6x-16)) ?

The domain of y=(-5x^2-7x)/(sqrt(6x-16)) is x> 8/3

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domain of y=(-5x^2-7x)/(sqrt(6x-16))

domain

y = \frac{- 5 x ^{2} - 7 x}{6 x - 16}

x > \frac{8}{3}

Interval Notation

(\frac{8}{3}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq \frac{8}{3}

Find undefined (singularity) points:

x = \frac{8}{3}

Combine real regions and undefined points for final function domain

x > \frac{8}{3}

g (x) = lo g_{17} (x)

f (x) = x \cdot sin (x)

f (x) = - \frac{4}{x} + 1

f (x) = \frac{x ^{2} - 16}{x ^{2} - 25}

\frac{2 x - 6}{x ^{2} + 7 - 4}

What is the domain of y=(-5x^2-7x)/(sqrt(6x-16)) ?
The domain of y=(-5x^2-7x)/(sqrt(6x-16)) is x> 8/3