What is the domain of f(x)=(x+3)^2+(y+6)^2=16 ?

The domain of f(x)=(x+3)^2+(y+6)^2=16 is -infinity <x<infinity

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=(x+3)^2+(y+6)^2=16

domain

f (x) = (x + 3)^{2} + (y + 6)^{2} = 16

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = \frac{x ^{2} + 2 x - 8}{x + 2}

f (x) = ln ∣ x - 1 ∣

f (x) = \frac{1}{5 - x}

f (x) = \frac{( x ^{2} - 4 x + 4 )}{x ^{2} - 4}

f (x) = - 2 x^{2} + 3 x - 1

What is the domain of f(x)=(x+3)^2+(y+6)^2=16 ?
The domain of f(x)=(x+3)^2+(y+6)^2=16 is -infinity <x<infinity