What is the domain of f(x)=ln(1/(x-6)) ?

The domain of f(x)=ln(1/(x-6)) is x>6

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domain of f(x)=ln(1/(x-6))

domain

f (x) = ln (\frac{1}{x - 6})

x > 6

Interval Notation

(6, \infty)

Solution steps

Find positive values for logs:

x > 6

Find undefined (singularity) points:

x = 6

Combine real regions and undefined points for final function domain

x > 6

y = 2 x + 3

f (x) = (\frac{4 x}{5 ( x - 2 ) ( x - 7 )})

f (x) = - 2 x^{2} + 3 x + 6

f (x) = (\frac{1}{x ^{2} - 2}) + 2

\frac{x}{( x - 3 ) ( x - 7 )}