What is the domain of f(x)= 1/(x-2)g(x)= 8/(x+3) ?

The domain of f(x)= 1/(x-2)g(x)= 8/(x+3) is x -3

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domain of f(x)= 1/(x-2)g(x)= 8/(x+3)

domain

f (x) = \frac{1}{x - 2} g (x) = \frac{8}{x + 3}

x < - 3 or x > - 3

Interval Notation

(- \infty, - 3) \cup (- 3, \infty)

Solution steps

Find undefined (singularity) points:

x = - 3

The function domain

x < - 3 or x > - 3

f (x) = \frac{2 x ^{2} + x - 1}{x ^{2} + x - 2}

y = 5 cos (x)

\frac{3 x - 7}{8}

g (x) = \frac{x + 2}{x ^{2} - 25}

f (x) = \frac{x ^{2} - 1}{x ^{3} - 8}

What is the domain of f(x)= 1/(x-2)g(x)= 8/(x+3) ?
The domain of f(x)= 1/(x-2)g(x)= 8/(x+3) is x<-3\lor x>-3