What is the domain of f(x)=(82)/((1-9x)^2) ?

The domain of f(x)=(82)/((1-9x)^2) is x 1/9

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domain of f(x)=(82)/((1-9x)^2)

domain

f (x) = \frac{82}{( 1 - 9 x ) ^{2}}

x < \frac{1}{9} or x > \frac{1}{9}

Interval Notation

(- \infty, \frac{1}{9}) \cup (\frac{1}{9}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{1}{9}

The function domain

x < \frac{1}{9} or x > \frac{1}{9}

f (x) = f (x) = ln (25 - x^{2})

f (x) = \frac{x ^{2} + 2}{x ^{2} - 1}

f (x) = 2 x - x^{3}

f (x) = lo g_{10} (\frac{3 + x}{3 - x})

\frac{1}{x ( x ^{2} - 49 )}

What is the domain of f(x)=(82)/((1-9x)^2) ?
The domain of f(x)=(82)/((1-9x)^2) is x< 1/9 \lor x> 1/9