What is the domain of (x^2-3x-4)/(2x^2+4x) ?

The domain of (x^2-3x-4)/(2x^2+4x) is x 0

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domain of (x^2-3x-4)/(2x^2+4x)

domain

\frac{x ^{2} - 3 x - 4}{2 x ^{2} + 4 x}

x < - 2 or - 2 < x < 0 or x > 0

Interval Notation

(- \infty, - 2) \cup (- 2, 0) \cup (0, \infty)

Solution steps

Find undefined (singularity) points:

x = 0, x = - 2

The function domain

x < - 2 or - 2 < x < 0 or x > 0

\frac{1}{3 x + 2} + 1

f (x) = - 2 - x + 5

f (x) = - 1 + lo g_{2} (x + 3)

y = (\frac{1}{2})^{x} + 2

y = lo g_{10} (7 - 2 x)

What is the domain of (x^2-3x-4)/(2x^2+4x) ?
The domain of (x^2-3x-4)/(2x^2+4x) is x<-2\lor-2<x<0\lor x>0