What is the domain of y/(3y^2+17y+10) ?

The domain of y/(3y^2+17y+10) is y -2/3

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domain of y/(3y^2+17y+10)

domain

\frac{y}{3 y ^{2} + 17 y + 10}

y < - 5 or - 5 < y < - \frac{2}{3} or y > - \frac{2}{3}

Interval Notation

(- \infty, - 5) \cup (- 5, - \frac{2}{3}) \cup (- \frac{2}{3}, \infty)

Solution steps

Find undefined (singularity) points:

y = - \frac{2}{3}, y = - 5

The function domain

y < - 5 or - 5 < y < - \frac{2}{3} or y > - \frac{2}{3}

f (x) = 11

f (x) = - \frac{5}{x}

f (x) = 10 x e^{- 5 x}

3 x^{4} - 4 x^{3} - 12 x^{2}

f (x) = \frac{1}{4 x ^{2} - 2 x - 8}

What is the domain of y/(3y^2+17y+10) ?
The domain of y/(3y^2+17y+10) is y<-5\lor-5<y<-2/3 \lor y>-2/3