What is the domain of f(x)=(sqrt(1+3)(1^2-1))/2 ?

The domain of f(x)=(sqrt(1+3)(1^2-1))/2 is -infinity <x<infinity

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domain of f(x)=(sqrt(1+3)(1^2-1))/2

domain

f (x) = \frac{1 + 3 ( 1 ^{2} - 1 )}{2}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

4 + \frac{1}{x}

x^{2} - 16 x + 66

\frac{x + 6}{12 - x ^{2} - 25}

f (x) = \frac{2 x + 3}{5 x - 2}

f (x) = ln (x) (49 - x^{2})

What is the domain of f(x)=(sqrt(1+3)(1^2-1))/2 ?
The domain of f(x)=(sqrt(1+3)(1^2-1))/2 is -infinity <x<infinity