What is the domain of y=sqrt(169-x^2) ?

The domain of y=sqrt(169-x^2) is -13<= x<= 13

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domain of y=sqrt(169-x^2)

domain

y = 169 - x^{2}

- 13 \leq x \leq 13

Interval Notation

[- 13, 13]

Solution steps

Find non-negative values for radicals:

- 13 \leq x \leq 13

The function domain

- 13 \leq x \leq 13

f (t) = ln (3 - t)

- \frac{5}{x + 7}

\frac{6 x}{9 x + 1}

f (x) = sin (x + π)

f (x) = \frac{( x \cdot x + 1 )}{( x + 2 )}

What is the domain of y=sqrt(169-x^2) ?
The domain of y=sqrt(169-x^2) is -13<= x<= 13