What is the domain of f(x)= 9/(sqrt(8x+9)) ?

The domain of f(x)= 9/(sqrt(8x+9)) is x>-9/8

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domain of f(x)= 9/(sqrt(8x+9))

domain

f (x) = \frac{9}{8 x + 9}

x > - \frac{9}{8}

Interval Notation

(- \frac{9}{8}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - \frac{9}{8}

Find undefined (singularity) points:

x = - \frac{9}{8}

Combine real regions and undefined points for final function domain

x > - \frac{9}{8}

g (x) = \frac{x}{x ^{2} + 36}

f (x) = 2 x^{2} - 2 x + 1

\frac{900}{56}

\frac{1}{4 - 2 x}

f (x) = \frac{4 - x}{4 + x}

What is the domain of f(x)= 9/(sqrt(8x+9)) ?
The domain of f(x)= 9/(sqrt(8x+9)) is x>-9/8