What is the domain of f(x)=sqrt((2x)/(x+5)-1) ?

The domain of f(x)=sqrt((2x)/(x+5)-1) is x = 5

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domain of f(x)=sqrt((2x)/(x+5)-1)

domain

f (x) = \frac{2 x}{x + 5} - 1

x < - 5 or x \geq 5

Interval Notation

(- \infty, - 5) \cup [5, \infty)

Solution steps

Find non-negative values for radicals:

x < - 5 or x \geq 5

Find undefined (singularity) points:

x = - 5

Combine real regions and undefined points for final function domain

x < - 5 or x \geq 5

\frac{2 x - 9}{lo g _{10} ( x + 3 )}

f (x) = lo g_{2} (x - 2) + 3

f (x) = \frac{x + 5}{- 3 x - 3}

\frac{x + 6}{x ^{2} + 5 x - 6}

f (x) = x 36 - x^{2}

What is the domain of f(x)=sqrt((2x)/(x+5)-1) ?
The domain of f(x)=sqrt((2x)/(x+5)-1) is x<-5\lor x>= 5