What is the domain of f(t)=sqrt(t^2+2t-8) ?

The domain of f(t)=sqrt(t^2+2t-8) is t = 2

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domain of f(t)=sqrt(t^2+2t-8)

domain

f (t) = t^{2} + 2 t - 8

t \leq - 4 or t \geq 2

Interval Notation

(- \infty, - 4] \cup [2, \infty)

Solution steps

Find non-negative values for radicals:

t \leq - 4 or t \geq 2

The function domain

t \leq - 4 or t \geq 2

f (x) = \frac{x + 9}{x ^{2} + 16}

y = - \frac{5}{6 ^{2}} (∣ x ∣ - 17)^{2} + 5

f (x) = - x^{2} + 10 x - 5

f (x) = \frac{1}{( 1 + e ^{- x} )}

f (x) = \frac{x}{( 1 + ∣ x ∣ )}

What is the domain of f(t)=sqrt(t^2+2t-8) ?
The domain of f(t)=sqrt(t^2+2t-8) is t<=-4\lor t>= 2