What is the domain of f(x)=(x+3)/(x^2+9x+18) ?

The domain of f(x)=(x+3)/(x^2+9x+18) is x -3

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domain of f(x)=(x+3)/(x^2+9x+18)

domain

f (x) = \frac{x + 3}{x ^{2} + 9 x + 18}

x < - 6 or - 6 < x < - 3 or x > - 3

Interval Notation

(- \infty, - 6) \cup (- 6, - 3) \cup (- 3, \infty)

Solution steps

Find undefined (singularity) points:

x = - 3, x = - 6

The function domain

x < - 6 or - 6 < x < - 3 or x > - 3

f (x) = 2 x^{2} + 8 x - 5

f (x) = 9 x + 2

f (x) = ln (\frac{4 x - 8}{2 x + 4})

f (x) = 2 x^{2} + 8 x + 1

f (x) = 2 x^{2} + 8 x + 5

What is the domain of f(x)=(x+3)/(x^2+9x+18) ?
The domain of f(x)=(x+3)/(x^2+9x+18) is x<-6\lor-6<x<-3\lor x>-3