What is the domain of f(x)=ln(x^2)-ln(2x+8) ?

The domain of f(x)=ln(x^2)-ln(2x+8) is -4 0

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domain of f(x)=ln(x^2)-ln(2x+8)

domain

f (x) = ln (x^{2}) - ln (2 x + 8)

- 4 < x < 0 or x > 0

Interval Notation

(- 4, 0) \cup (0, \infty)

Solution steps

Find positive values for logs:

- 4 < x < 0 or x > 0

The function domain

- 4 < x < 0 or x > 0

f (x, y) = 3

f (x) = (x^{2} - 6 x)^{\frac{1}{5}}

f (x) = \frac{x ^{2}}{x ^{4} + 3}

- x^{2} - 2 x + 15

f (x) = \frac{4 + x}{e ^{c o s (x)}}

What is the domain of f(x)=ln(x^2)-ln(2x+8) ?
The domain of f(x)=ln(x^2)-ln(2x+8) is -4<x<0\lor x>0