What is the domain of f(x)=(sqrt(x-5))^2 ?

The domain of f(x)=(sqrt(x-5))^2 is x>= 5

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domain of f(x)=(sqrt(x-5))^2

domain

f (x) = (x - 5)^{2}

x \geq 5

Interval Notation

[5, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 5

The function domain

x \geq 5

1 + \frac{9 x - 70}{x ^{2} - 15 x + 56}

f (x) = \frac{x ^{2} - 3 x + 2}{x ^{2} - 1}

\frac{- 1}{x}

f (x) = 2 x = 5

\frac{x ^{2} - 11}{36 x ^{2} - 6 x - 6}

What is the domain of f(x)=(sqrt(x-5))^2 ?
The domain of f(x)=(sqrt(x-5))^2 is x>= 5