What is the domain of f(x)=(1+x^4)/(x^2-x^4) ?

The domain of f(x)=(1+x^4)/(x^2-x^4) is x 1

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domain of f(x)=(1+x^4)/(x^2-x^4)

domain

f (x) = \frac{1 + x ^{4}}{x ^{2} - x ^{4}}

x < - 1 or - 1 < x < 0 or 0 < x < 1 or x > 1

Interval Notation

(- \infty, - 1) \cup (- 1, 0) \cup (0, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 0, x = 1, x = - 1

The function domain

x < - 1 or - 1 < x < 0 or 0 < x < 1 or x > 1

f (x) = - e^{x - 2}

f (x) = - (x - 1)^{3} (x + 3)^{2}

f (x) = \frac{x ^{2}}{x ^{4} + 2}

f (x) = \frac{x}{x + 10}

y = (x + 1)^{2} + (y - 2)^{2} = 49

What is the domain of f(x)=(1+x^4)/(x^2-x^4) ?
The domain of f(x)=(1+x^4)/(x^2-x^4) is x<-1\lor-1<x<0\lor 0<x<1\lor x>1