What is the domain of log_{2}(x(2x-3)) ?

The domain of log_{2}(x(2x-3)) is x 3/2

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domain of log_{2}(x(2x-3))

domain

lo g_{2} (x (2 x - 3))

x < 0 or x > \frac{3}{2}

Interval Notation

(- \infty, 0) \cup (\frac{3}{2}, \infty)

Solution steps

Find positive values for logs:

x < 0 or x > \frac{3}{2}

The function domain

x < 0 or x > \frac{3}{2}

y 2 (x - 1) (x - 3) = 4

4^{x} - 1

\frac{4 x - 12}{3}

f (x) = \frac{2 x - 5}{x ^{2} - 6 x}

y = \frac{x}{1 - ln ( x - 8 )}

What is the domain of log_{2}(x(2x-3)) ?
The domain of log_{2}(x(2x-3)) is x<0\lor x> 3/2