What is the domain of 1/(sqrt(8x-16)) ?

The domain of 1/(sqrt(8x-16)) is x>2

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domain of 1/(sqrt(8x-16))

domain

\frac{1}{8 x - 16}

x > 2

Interval Notation

(2, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 2

Find undefined (singularity) points:

x = 2

Combine real regions and undefined points for final function domain

x > 2

f (x) = \frac{x}{4} - 1

y = x + 11 + 5

m c^{2}

y = 3 x^{2} - 6 x + 9

\frac{1}{e ^{x}}