What is the domain of f(x)=sqrt((x+6)/((x-2)(x+3))) ?

The domain of f(x)=sqrt((x+6)/((x-2)(x+3))) is -6 2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=sqrt((x+6)/((x-2)(x+3)))

domain

f (x) = \frac{x + 6}{( x - 2 ) ( x + 3 )}

- 6 \leq x < - 3 or x > 2

Interval Notation

Solution steps

Find non-negative values for radicals:

- 6 \leq x < - 3 or x > 2

Find undefined (singularity) points:

x = 2, x = - 3

Combine real regions and undefined points for final function domain

- 6 \leq x < - 3 or x > 2

f (x) = \frac{x ^{2} + 2}{x - 7}

f (x) = \frac{2 x + 2}{3 x + 10}

\frac{x ^{2} - 2 x + 6}{( x ^{2} + 2 ) ( x - 2 )}

f (x) = 3 \cdot x^{\frac{2}{3}} - 2 x

f (x) = lo g_{10} (\frac{2}{3} x - 4)

What is the domain of f(x)=sqrt((x+6)/((x-2)(x+3))) ?
The domain of f(x)=sqrt((x+6)/((x-2)(x+3))) is -6<= x<-3\lor x>2